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## Comment on

Testing Possible Cases## Hi Brent,

Need your help: https://gmatclub.com/forum/if-m-p-s-and-v-are-positive-and-m-p-s-v-which-of-the-following-160298.html

I tried solving it by input-output method and I don't think that's the best approach for it. I chose the following values: m = 3; p = 5; s = 7; v = 2

## Question link: https:/

Question link: https://gmatclub.com/forum/if-m-p-s-and-v-are-positive-and-m-p-s-v-which...

Yeah, the input-output method MAY help you eliminate some answer choices, but it won't take you all the way to the correct answer.

Here's my full solution: https://gmatclub.com/forum/if-m-p-s-and-v-are-positive-and-m-p-s-v-which...

Cheers,

Brent

## Hey Brent :) Can you give me

## My solution to question 390:

My solution to question 390: https://gmatclub.com/forum/a-school-administrator-will-assign-each-stude...

My solution to question 176: https://gmatclub.com/forum/if-n-3-8-2-8-which-of-the-following-is-not-a-...

Aside: Here are links to solutions to ALL official guide questions: https://gmatclub.com/forum/gmac-official-guides-the-master-directory-lin...

Cheers,

Brent

## https://gmatclub.com/forum/if

Hi Brent. I just wanted to say thank you for all these videos and resources. If I had looked at the above linked questions before taking your course, I would have been in shock. But now I am having much much greater success.

## Good to hear!!

Good to hear!!

## Hi Brent,

Please review my solution.

statement 1: xy+y=ODD ; y(x+1)=Odd . This implies y= odd and x+1 = odd. If x+1=odd then x= even.(sufficient)

statement 2: 6x-3y=ODD; 3(2x-y)=odd. We know 3 is odd.(2x-y)=Odd ; x can be even or x can be odd. (Not sufficient)

So, opt A is the correct ans.

## That's a perfectly-reasoned

That's a perfectly-reasoned solution. In fact, it's exactly how I'd solve such a question.

That said, if students aren't sure how to proceed with similar questions, they can always just test all possible cases as we have done above.

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