Question: Ages of Ann, Bea and Cho

Comment on Ages of Ann, Bea and Cho

Couldn't you put 9 and 1 as the other two numbers in the third example in the second case, making 9 the median? In which case, it wouldn't be sufficient. I would imagine the two cases together give you at least two ages, allowing you solve the equation you created initially, which in turn, yields a median. I'm a little confused.
gmat-admin's picture

If we made 9 and 1 the other two values in the third example (for statement 2), then the three numbers would be {1, 9, 10}, in which case the average would NOT equal 10 (one of the given conditions).

I see the way you did it. When i answered it though I thought they were each insufficient because there were 2 unknowns, but then combined it was easy to determine the 3rd age and then definitively answer the target question.
gmat-admin's picture

Yes, that's an easy trap to fall into :-)

Cheers,
Brent

I wish this test wasn't all about trying to trick us!
gmat-admin's picture

Ha! Yes, it certainly seems that way at times!!

Cheeky. So very cheeky. Fell for the trap and went with C!
gmat-admin's picture

It's an enticing answer choice!!

Hi brent,
I have learned that in arithmetic sequence the mean is always equal to median if its in odd number of sequence please correct me if i am wrong
gmat-admin's picture

You're partially correct.
For ALL sequences in which the values are EQUALLY SPACED, the mean = the median.
It doesn't matter whether we have an odd or even number of values.
For example, in the set {3, 8, 13, 18}, the mean = the median = 10.5

This is covered in the following video: https://www.gmatprepnow.com/module/gmat-statistics/video/804

By the way, the GMAT doesn't expect students to know the term "arithmetic sequence."

Cheers,
Brent

Darn it Brent, made the mistake of choosing C. Great question.

Also, thanks for this comment. In your previous video, there was a reinforcement question that heeded to this rule which you explained in your gmat club solution but definitely had no idea how to solve without that rule.

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