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## Comment on

Eliminating Fractions## How do we find the least

https://gmatclub.com/forum/which-of-the-following-has-the-greatest-value-248206.html

## Question link: https:/

Question link: https://gmatclub.com/forum/which-of-the-following-has-the-greatest-value...

I knew that the least common multiple of the five denominators will consist of powers of 5 and 7.

First, since the biggest power of 5 is 5^5, the least common multiple must have 5^5

Likewise, since the biggest power of 7 is 7^5, the least common multiple must have 7^5.

Does that help?

Cheers,

Brent

## It was nice to see this

## I tried to solve the equation

## Let's try it.

Let's try it.

GIVEN: (3x + 2)/2 - (x + 1)/3 = x

Rewrite fractions with common denominators.

Take (3x + 2)/2 and multiply top and bottom by 3 to get the EQUIVALENT fraction (9x + 6)/6

Take (x + 1)/3 and multiply top and bottom by 2 to get the EQUIVALENT fraction (2x + 2)/6

Our equation becomes: (9x + 6)/6 - (2x + 2)/6 = x

Combine numerators to get: (7x + 4)/6 = x

Multiply both sides by 6 to get: 7x + 4 = 6x

Solve: x = -1

Does that help?

Cheers,

Brent

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