# Question: Value of x

## Comment on Value of x

### For the 30:60:90 Triangle,

For the 30:60:90 Triangle, does it matter which leg we use for 1 and √3? In your base triangle,√3 is on the base. Could is also work if √3 is on the other leg? Thanks! ### The 3 sides in a 30:60:90

The 3 sides in a 30:60:90 triangle have lengths 1, √3, and 2, and there is a strict rule for which sides have which length.

In an earlier lesson (https://www.gmatprepnow.com/module/gmat-geometry/video/860), we learned that, in a triangle, the longest side is the side opposite the biggest angle, and the shortest side is the side opposite the smallest angle.

So, in a 30:60:90 triangle, the shortest side is opposite the smallest angle (30 degrees). So, the side opposite the 30-degree angle must have length 1.

Likewise, the side opposite the 60-degree angle must have length √3, and the side opposite the 90-degree angle must have length 2.

### is there a way to solve this

is there a way to solve this using 2 equations and solving them for x ### What 2 equations do you have

What 2 equations do you have in mind?

### I got the correct answer

I got the correct answer using ratio 1/2 = (x+1)/(4x-3)

Why did you use the ratio above, instead of that? ### Your ratios work as well.

You're comparing the shortest side (x+1) and the hypotenuse (4x-3) on the LARGER triangle with the shortest side (1) and the hypotenuse (2) on the SMALLER triangle.

I'm comparing corresponding sides.

As long as you keep the order straight, either solution is fine.

### Just an idea, but could the

Just an idea, but could the Pythagorean theorem work here to find "x"? For example: x+1 squared plus 4x-3 squared = √3(x+1) squared? ### Great idea. We know that, in

Great idea. We know that, in the 30-60-90 right triangle, the length of the missing side will be √3 times the length of the side opposite the 30-degree angle (x+1)

So, the length of the missing side is √3(x+1)

Let's keep going.

First, we'll apply the Pythagorean theorem...
We get: (x + 1)² + [√3(x+1)]² = (4x - 3)²
Expand: x² + 2x + 1 + 3x² + 6x + 3 = 16x² - 24x + 9
Simplify: 4x²+ 8x + 4 = 16x² - 24x + 9
Rearrange to get: 12x² - 32x + 5 = 0
Factor (ugh!) to get: (6x - 1)(2x - 5)
Solve: EITHER x = 1/6 OR x = 5/2

Notice that, if x = 1/6, then the length of the hypotenuse (4x - 3) is NEGATIVE (which makes no sense).
So, we can ELIMINATE the solution x = 1/6, which means the correct answer is x = 5/2

So the Pythagorean Theorem works here. The only problem is that we must content with the tricky quadratic equation, 12x² - 32x + 5 = 0

Cheers,
Brent

### OUCh! I think I'll stick with

OUCh! I think I'll stick with your method.