Question: N=5314+k

Comment on N=5314+k

Hi Brent I noticed a easier way to do this
Since the possible values of k is evenly spread. The sum for each of N term will be greater by 1. So if the value of the second Nth term is divisible by 3 then we know the next one divisible by 3 will be the 5th Nth term. So for 4 it will be every 4th Nth term.

So this way we could save time in solving the question.
gmat-admin's picture

That certainly works. Good thinking!

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