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## Comment on

Is x Even## For statement 2, I plugged in

## Can you show me your

Can you show me your calculations. I ask, because I think your calculations might be off.

Statement 2: 6x - 3y is odd

- case a: if x is even and y is odd, then 6x - 3y is ODD. In this case, x IS even

- case b: if x is odd and y is even, then 6x - 3y is ODD. In this case, x is NOT even

Both cases satisfy statement 2, but each case yields a different answer to the target question. This means statement 2 is not sufficient.

## can statement 2 be solved

## Be careful. Statement 2 does

Be careful. Statement 2 does talk about the difference between x and y; it talks about the difference between 6x and 3y. Since 6x must be EVEN, we can conclude that y is odd.

If the target question had asked "Is y odd?", your approach would have found statement 2 to be insufficient, when it would have been sufficient.

## For statement 1, if I look at

## Your first statement is true.

Your first statement is true.

However, your second statement is not true: Alternatively, if y=even, then x will have to be odd since first term has to be odd.

If y is even, then the first term (xy) will be even, regardless of the value of x.

This tells us that, if xy+y is odd, then y must be odd.

Cheers,

Brent

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