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## Comment on

Remainder when Divided by 7## My approach was similar to

## Great approach!

Great approach!

## My approach is like this.

Once we equate both equations of x, we get 5q = 7k. Once looking at this, we will get 35 in our mind where 5 and 7 meets. So q=7 and k=5.

Then, q/7 means 7/7 which leaves remainder 0.

## Great approach.

Great approach.

## https://gmatclub.com/forum

here sir i did this

unit digit of 12^12= 6

unit digit of 13^13 = 3

unit digit of 12^12 +13^13 will be 9

and unit digit of (14^14*15^15) will be 0

but 14^14*15^15 > 12^12+13^13

when we subtract two numbers last digit would be 10-9 = 1

eg 20-9 last digit will be 1 30-9 will be 1

sir is this approach correct?

## That's a perfectly valid

That's a perfectly valid solution. Nice work!

Cheers,

Brent

## dear Brent what will happen

## Great question! Let's find

Great question! Let's find out what happens.

GIVEN: When positive integer x is divided by 5, the quotient is q and the remainder is 1.

If x = 1, then q = 0 (since 5 divides into 1 ZERO times with remainder 1)

QUESTION: What is the remainder when q is divided by 7?

Since q = 0, the remainder will be 0, when 0 is divided by 7.

Answer: A

Cheers,

Brent

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