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Simplifying Roots## i am facing an issue

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## Good day

one issue I have is determining the primes to use for large numbers such as the 756, because I mean it could take forever to try and test different prime number to get to such a large number.

Any time saving recommendations?

Thanks

## Hi Schalla14,

Hi Schalla14,

You'll see that, to factor 756, you need only know the divisibility rules for 2 and 3. So, it shouldn't take long to find the prime factorization.

On test-day, you won't be required to simplify the square root of a large number that has, within it, big prime factors. For example, you wouldn't need to deal with something like √2023.

ASIDE: 2023 = (17)(17)(7)

So, √2023 = √(17²)(7)

= (√17²)(√7)

= 17√7

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