Have questions about your preparation or an upcoming test? Need help modifying the Study Plan to meet your unique needs? No problem. Just book a Skype meeting with Brent to discuss these and any other questions you may have.

- Video Course
- Video Course Overview - READ FIRST
- General GMAT Strategies - 7 videos (all free)
- Data Sufficiency - 16 videos (all free)
- Arithmetic - 38 videos (some free)
- Powers and Roots - 36 videos (some free)
- Algebra and Equation Solving - 73 videos (some free)
- Word Problems - 48 videos (some free)
- Geometry - 42 videos (some free)
- Integer Properties - 38 videos (some free)
- Statistics - 20 videos (some free)
- Counting - 27 videos (some free)
- Probability - 23 videos (some free)
- Analytical Writing Assessment - 5 videos (all free)
- Reading Comprehension - 10 videos (all free)
- Critical Reasoning - 38 videos (some free)
- Sentence Correction - 70 videos (some free)
- Integrated Reasoning - 17 videos (some free)

- Study Guide
- Your Instructor
- Office Hours
- Extras
- Prices

## Comment on

Root in the Denominator## I solved this in a slightly

So instead of trying to get the same denominator as 1 by using two conjugates, I multiplied both the denominators with each other to get a common multiple in the denominator, and then in the numerators, I multiplied the first fraction's numerator by the second denominator, and similarly for the other one.

Do let me know.

Thanks

## That works too.

That works too.

Your method works because the each of the two denominators just happens to be the conjugate of the other.

## Hey!

Thanks for the response.

Just a follow up question. Will my method not work, in case they are not conjugates?

## Yes, yours is still a valid

Yes, yours is still a valid approach, but you may have to perform a little extra work (not much though).

## Add a comment