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## Comment on

Introduction to Probability## is the solution to the last

1/5 (is the chance that he will be selected first) ,

4/5 x 1/4 = 4/20 = 1/5 (is the chance that he will be selected second) ...

1/5 + 1/5 = 2/5 = 4/10 = 0.4

## That's a perfect approach.

That's a perfect approach. Since this video is an introduction to probability, we don't get into any techniques yet, other than to explain what probability is all about.

## Brent, I've got a hard

"If an integer 'n' is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that n(n+1)(n+2) will be divisible by 8?"

A: 1/4

B: 3/8

C: 1/2

D: 5/8

E: 3/4

OA: D

## This question has been

This question has been discussed many times on the GMAT discussions forums.

You'll find 4 or 5 diverse solutions from experts here: http://www.beatthegmat.com/if-an-integer-n-is-to-be-chosen-at-random-fro...

## Thanks brent, much

## Hi Brent.

For the last question:

The denominator would be 5C2=10

The numerator for the two-person selections including Amir will be say =1*4C1. (fix Amir as one (1) and variate the other person selected (simple combination without order).

So answer would be 1*4c1/5c2 = 4/10.

Now, How this formula will work for below mentioned question?

Two people are randomly selected from the group of five people: Amir, Brian, Claudia, Dhana and Ebo. What is the probability that Amir & Brian is selected?

Please tell me where I'm wrong in above mentioned formula?

2 people are fixed, so nominator would be 2x3C0 = 2

and denominator would be 5C2.

Answer would be 2/10. Which is wrong I know because only 1 group can be formed with Amir and Brian.

Where I'm wrong to understand this formula? am I wrong with Denominator?

## Your new question: Two people

Your new question: Two people are randomly selected from the group of five people: Amir, Brian, Claudia, Dhana and Ebo. What is the probability that Amir & Brian are BOTH selected?

The correct answer to that question is 1/10. You're getting 2/10 as your answer, because you're treating the numerator different from the way you're treating the denominator.

For the denominator, you say there are 10 ways to select 2 people from 5 people. You used COMBINATIONS (5C2 to be exact), because you are saying that the ORDER in which we select the two people does not matter. For example, selecting Dhana first and Ebo 2nd, is the SAME as selecting Ebo first and Dhana 2nd. This is a perfectly fine approach.

However, for the numerator, you are used the Fundamental Counting Principle, in which you say there are 2 ways to select BOTH Amir and Brian. This means you are saying that the ORDER DOES matter. That is, you are saying that selecting Amir first and Brian 2nd, is DIFFERENT FROM selecting Brian first and Amir 2nd.

To get the correct answer, we must EITHER decide that order matters OR order does not matter, and then apply that strategy to the numerator AND the denominator.

If we go with your original solution (where the denominator is calculated as though order does NOT matter), then we must also treat the numerator the same way. If order does NOT matter, then we must determine the number of ways to select 2 people from a group of two people (Amir and Brian). Since order does not matter, we'll use combinations. We can select 2 people from 2 people in 2C2 ways. 2C2 = 1

So, P(both Amir and Brian are selected) = 1/10

-----------------------------------

ALTERNATIVELY, we can treat BOTH the numerator and denominator as though order DOES matter.

So, for the denominator, in how many ways can we select 2 people from 5 people?

We can select the 1st person in 5 ways

Then we can select the 2nd person in 4 ways

So, the TOTAL number of ways to select 2 people (if order DOES matter) = (5)(4) = 20

Then, for the numerator, in how many ways can we select 2 people from 2 people (Amir and Brian) if order DOES matter?

We can select the 1st person in 2 ways

Then we can select the 2nd person in 1 way

So, the TOTAL number of ways to select 2 people (if order DOES matter) = (2)(1) = 2

So, P(both Amir and Brian are selected) = 2/20 = 1/10

Does that help?

Cheers,

Brent

## Wow! what a quick response.

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