Have questions about your preparation or an upcoming test? Need help modifying the Study Plan to meet your unique needs? No problem. Just book a Skype meeting with Brent to discuss these and any other questions you may have.

- Video Course
- Video Course Overview
- General GMAT Strategies - 7 videos (free)
- Data Sufficiency - 16 videos (free)
- Arithmetic - 38 videos
- Powers and Roots - 36 videos
- Algebra and Equation Solving - 73 videos
- Word Problems - 48 videos
- Geometry - 42 videos
- Integer Properties - 38 videos
- Statistics - 20 videos
- Counting - 27 videos
- Probability - 23 videos
- Analytical Writing Assessment - 5 videos (free)
- Reading Comprehension - 10 videos (free)
- Critical Reasoning - 38 videos
- Sentence Correction - 70 videos
- Integrated Reasoning - 17 videos

- Study Guide
- Your Instructor
- Office Hours
- Extras
- Prices

## Comment on

Independent Events## A={2,3,4,5}

B={4,5,6,7,8}

Two integers will be randomly selected from the sets

above, one integer from set A and one integer from

set B. What is the probability that the sum of the two

integers will equal 9 ?

Hi can u pls explain this que. Im getting confused

## The best/fastest way to solve

The best/fastest way to solve this question is to apply the basic probability formula.

So, P(sum is 9) = (number of pairs that add to 9)/(total number of pairs)

As always, start with the denominator: total number of pairs

We can select a number from set A in 4 ways, and we can select a number from set B in 5 ways. So, the TOTAL number of pairs = 4 x 5 = 20

Now the numerator: number of pairs that add to 9

Let's list all possible pair:

- select 2 from set A, and 7 from set B

- select 3 from set A, and 6 from set B

- select 4 from set A, and 5 from set B

- select 5 from set A, and 4 from set B

So, there are 4 pairs that add to 9

So, P(sum is 9) = 4/20 = 1/5

For more information, watch https://www.gmatprepnow.com/module/gmat-probability/video/742

## Thanks Brent. Understood now

## Hi Brent,

How do I calculate the first example (selecting balls without replacement) if what I wanted to know was the probability of the second ball being green?

I mean, I understand that the two events are dependent, however, how can I know what is the probability of event B occurring if I don't know whether or not event A occurred.

What I got so far is:

If the first ball is green, then the probability of the second ball being green is: P(B|A) = 3/6 = 1/3

If the first ball is not green, then the probability of the second ball being green is: P(B|A) = 4/6 = 2/3

How do I reconcile these two probabilities into one?

## Sorry, I'm not 100% sure what

Sorry, I'm not 100% sure what probability you are trying to calculate.

If you want to calculate P(2nd ball is green), then we can say...

P(2nd ball is green) = P(1st ball is green and 2nd ball is green OR 1st ball is red and 2nd ball is green)

= P(1st ball is green AND 2nd ball is green) + P(1st ball is red AND 2nd ball is green)

= [P(1st ball is green) x P(2nd ball is green)] + [P(1st ball is red) x P(2nd ball is green)]

= [4/7 x 3/6] + [3/7 x 4/6]

= 12/42 + 12/42

= 24/42

= 4/7

ASIDE: Notice that P(2nd ball is green) is equal to P(1st ball is green). For more on this phenomenon see my post (7 posts down) at: http://www.beatthegmat.com/beat-this-probability-qs-t185719.html

Does that help?

## Hi Brent,

What I want to calculate is the probability of the second ball being green (similarly to the question on the post you mentioned).

It's clear now. I see where I went wrong.

Thanks

## Can you please help me with

Gordon buys 5 dolls for his 5 nieces. The gifts include two identical S beach dolls, one E, one G, one T doll. If the youngest niece doesn't want the G doll, in how many different ways can he give the gifts?

## Glad to help.

Glad to help.

You'll find my step-by-step solution here: http://www.beatthegmat.com/p-amp-c-problem-t269505.html

Cheers,

Brent

## Add a comment