Lesson: Determining Independence

Comment on Determining Independence

What is the answer for the 2 women selection?
gmat-admin's picture

P(both selections are women) = P(1st selection is a woman AND 2nd selection is a woman)
= (4/7)(3/6)
= 12/42
= 2/7

what is the answer for both tosses?
gmat-admin's picture

P(1st toss is heads AND 2nd toss is heads)
= P(1st toss is heads) x P(2nd toss is heads)
= 1/2 x 1/2
= 1/4

In the two women selection question
what's wrong with this method

prob = 3c2/7c2
order doesn't matter so why can't we use this method
gmat-admin's picture

Your solution is great, EXCEPT for the numerator (it's not 3C2).

P(both selections are women) = (number of ways to select 2 women from the FOUR women)/(number of ways to select 2 people from the 7 people)
= (4C2)/(7C2)
= 6/21
= 2/7

oh my bad
Thanks a lot :)

in the women case, even a selection of a man in the first chance impacts the probability of selection on a woman next (total number of people decreases).
gmat-admin's picture

That's true!

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