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## Comment on

Determining Independence## What is the answer for the 2

## P(both selections are women)

P(both selections are women) = P(1st selection is a woman AND 2nd selection is a woman)

= (4/7)(3/6)

= 12/42

= 2/7

## what is the answer for both

## P(1st toss is heads AND 2nd

P(1st toss is heads AND 2nd toss is heads)

= P(1st toss is heads) x P(2nd toss is heads)

= 1/2 x 1/2

= 1/4

## In the two women selection

what's wrong with this method

prob = 3c2/7c2

order doesn't matter so why can't we use this method

## Your solution is great,

Your solution is great, EXCEPT for the numerator (it's not 3C2).

P(both selections are women) = (number of ways to select 2 women from the FOUR women)/(number of ways to select 2 people from the 7 people)

= (4C2)/(7C2)

= 6/21

= 2/7

## oh my bad Thanks a lot :)

Thanks a lot :)

## in the women case, even a

## That's true!

That's true!

## Add a comment