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## Comment on

Range and Standard Deviation## I really like your videos.

## I have a question - you say

If you were to just take the absolute value of all the values minus the mean, and then divide them by n, would that be the same as the standard deviation?

## Nevermind, just watched the

## hi - maybe a silly error on

Average of 22. Take difference of each number (so absolute value of 1-22, 1-22, 3-22, and so on). Sum all those differences and divide by 10, the number of values in the set. I get ~20.6

## You are using the informal

You are using the informal definition to calculate the Standard Deviation of 20.6

I used the formal definition/formula to find that the Standard Deviation is approximately 24.6

On the GMAT, the informal definition is all you need (even though it yields a different SD)

## https://gmatclub.com/forum/if

Hi Brent, would you say using the informal definition here is what lead me to the wrong answer of picking choice 3 as sufficient? That is, I picked 0 as its eligible since we can take the negative number to be -1 and positive number to be 5, and them once we apply the informal definition, I got the "average distance away from the mean" to be 0. Hence I thought the choice 3 was valid .. but apparently not according to other posts.

## Question link: https:/

Question link: https://gmatclub.com/forum/if-m-is-a-negative-integer-and-k-is-a-positiv...

I think you're confusing the mean with average DISTANCE from the mean.

If we let -1 and 5 be M and K, then the set is: {-7, -5, -3, -1, 0, 1, 3, 5, 7}

Mean = 0

-7 is 7 units from the mean

-5 is 5 units from the mean

-3 is 3 units from the mean

-1 is 1 units from the mean

0 is 7 units from the mean

1 is 1 units from the mean

3 is 3 units from the mean

5 is 5 units from the mean

7 is 7 units from the mean

Average DISTANCE from the mean = (7 + 5 + 3 + 1 + 0 + 1 + 3 + 5 + 7)/9

= 32/9

≈ 3.5

Does that help?

Cheers,

Brent

## Yes I saw the video all over

## Hi Brent,

Could you please use your magic and explain the problem below. I'd really like your take on it. Thanks.

Set X and Y have 5 numbers, respectively.Is the S.D of X > S.D of Y?

1) Range of X > Range of Y

2) Average of X is greater than that of Y

## Good question.

Good question.

First note that the average (arithmetic mean) of each set has no bearing the S.D. of each set. For example, even though the average of the set {3,3,3,3,3} is greater than the average of the set {1,1,1,1,1}, their standard deviations are the same.

Now let's jump straight to...

STATEMENTS 1 AND 2 COMBINED

There are many sets that satisfy BOTH statements.

Consider these two possible cases:

CASE A: set X = {-2, -2, 0, 2, 2.1} and set Y = {-2, 0, 0, 0, 2}. In this case, the S.D. of set X IS GREATER THAN the S.D. of set Y.

CASE B: set X = {-2, 0, 0, 0, 2.1} and set Y = {-2, -2, 0, 2, 2}. In this case, the S.D. of set X IS LESS THAN the S.D. of set Y.

Since the COMBINED statements are insufficient, the correct answer is E

Cheers,

Brent

## Thanks Brent

Just needed to see a couple more examples than what was provided on the practice sites to get it in my head. This is a really good practice problem that helps you to truly understand.

Thanks again

## Hi,

Can the Standard Deviation be equal to Mean?

Thanks

## Yes, that's possible. The

Yes, that's possible. The most immediate example that comes to mind is a set of zeros {0, 0, 0, 0, 0}

Here, the mean = 0 and the standard deviation = 0.

Cheers,

Brent

## Hi Brent, could you please

The median number of business trips for 6 employees in a certain quarter is 10. The range of number of business trips for those employees that quarter is 9.

Determine whether the following statement is true, is false, or does not contain enough information: The fewest business trips could be 0.

## If we list the number of

If we list the number of trips taken by each employee, we will have a list of SIX NUMBERS.

If we write the values in ASCENDING order, let's say they look like this: {a, b, c, d, e, f}

Since we have an EVEN number of values, the median is the average of the 2 middlemost values.

So, we can write: (c + d)/2 = 10

There are two possible cases to consider:

CASE A: c = 10 and d = 10

CASE B: c is less than 10 and d is greater than 10

CASE A: If the RANGE of values is 9, one of the values is 10, then the SMALLEST POSSIBLE number must be greater than or equal to 1.

So, it's IMPOSSIBLE for the smallest value to be 0

CASE B: If the RANGE of values is 9, one of the values is greater than 10, then the SMALLEST POSSIBLE number must be greater than 1.

So, it's IMPOSSIBLE for the smallest value to be 0

So, as we can see, it's impossible for the fewest business trips to be 0.

Cheers,

Brent

## Is the variance not tested by

Thank you,

Ana

## The test-makers say that

The test-makers say that variance is tested on the GMAT, but I've never seen an official question that actually tests it (other than a question in the Diagnostic test in the Official Guide for GMAT Review).

Variance is covered in this video: https://www.gmatprepnow.com/module/gmat-statistics/video/809

Interquartile range is NOT tested.

Cheers,

Brent

## https://gmatclub.com/forum/is

Hi Brent, aren't the standard deviations for case B of your solution toward the end = 0? Rather than greater? Thank you. Please correct me if I am wrong. Thanks beforehand!

## Link to my solution: https:/

Link to my solution: https://gmatclub.com/forum/is-the-standard-deviation-of-a-less-than-the-...

I'm not sure what you mean.

The only time we get a standard deviation of ZERO is when all of the values in the set are EQUAL.

Which set are you referring to?

Cheers,

Brent

## https://gmatclub.com/forum/if

Hi Brent, does the question want us to assume the numbers to be in an ascending or descending manner? And I do not understand when you mentioned that if we add more numbers to the set, the range doesn't change ..

You have example of 3,10 and the range to be 7. However, if we add an element say 2, doesn't the range change from being 7 to an 8?

Sorry for the lengthy question!

## Link to my solution: https:/

Link to my solution: https://gmatclub.com/forum/if-s-is-a-set-of-four-numbers-x-y-z-and-w-is-...

I didn't say "if we add more numbers to the set, the range doesn't change"

I said:

"The set {3, 10} has a range of 7

If we ADD more values to the set, we cannot make the range LESS THAN 7"

Likewise, for statement 1, we learn that the range of the set {x, w} is GREAT THAN 4

So, if we add more values to that set, the range cannot become less than 4.

Does that help?

Cheers,

Brent

## https://gmatclub.com/forum/a

Hi Brent, why can it not be option C? Cos then we are only 0 units away from the mean ... If you could explain with a different approach, it would be particularly helpful!

Thanks beforehand.

## Question link: https:/

Question link: https://gmatclub.com/forum/a-set-of-data-consists-of-the-following-5-num...

We want the NEW standard deviation (with the addition of two more numbers) to be close to the ORIGINAL standard deviation.

After some informal calculations, we see that the ORIGINAL standard deviation is about 2.4

In other words, in the ORIGINAL set of numbers, the average distance from the mean is about 2.4

So, in order for the NEW standard deviation to be close to 2.4, we need each of the two ADDITIONAL values to be about 2.4 away from the mean.

The mean = 4

3 is 1 units from the mean

5 is 1 units from the mean

On the other hand,

2 is 2 units from the mean

6 is 2 units from the mean

So, the addition of 2 and 6 (which are both 2 units from the mean) will change the standard deviation LESS THAN the addition of 3 and 5 (which are both 1 unit from the mean)

Does that help?

Cheers,

Brent

## Yes that is very clear! Thank

## https://gmatclub.com/forum/if

What if K amd M equal -1 and 5. then SD could be 0 right?

## Question link: https:/

Question link: https://gmatclub.com/forum/if-m-is-a-negative-integer-and-k-is-a-positiv...

Not quite. If K = -1 and M = 5, then the MEAN (not the standard deviation) is zero.

In order for the standard deviation of a set to be zero, all numbers in that set must be the SAME.

For example, the set {3,3,3,3,3,3} has standard deviation zero.

Does that help?

Cheers,

Brent

## Oh yes. I keep thinking that

Thanks!

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