If you have any questions, ask them on the Beat The GMAT discussion forums. The average response time is typically __less than 30 minutes__.

- GMAT Video Course
- Video Course Overview - READ FIRST
- General GMAT Strategies - 7 videos (all free)
- Data Sufficiency - 16 videos (all free)
- Arithmetic - 38 videos (some free)
- Powers and Roots - 36 videos (some free)
- Algebra and Equation Solving - 73 videos (some free)
- Word Problems - 48 videos (some free)
- Geometry - 42 videos (some free)
- Integer Properties - 38 videos (some free)
- Statistics - 20 videos (some free)
- Counting - 27 videos (some free)
- Probability - 23 videos (some free)
- Analytical Writing Assessment - 5 videos (all free)
- Reading Comprehension - 10 videos (all free)
- Critical Reasoning - 38 videos (some free)
- Sentence Correction - 70 videos (some free)
- Integrated Reasoning - 17 videos (some free)

- Learning Guide
- Extra Resources
- Guarantees
- About
- Get Started

## Comment on

Multiple Trips or Multiple Travelers## Two trains, X and Y, started

(A) 37.5

(B) 40.0

(C) 60.0

(D) 62.5

(E) 77.5 Don't know what should be done after taking out per hour speed of x and y

## There are some very nice

There are some very nice solutions here: http://www.beatthegmat.com/trains-from-two-opposite-ends-t286355.html

Please let me know if you need any clarification.

## Speed of Train X 20kmph and

So,Train X would travel 20*15/8=37.5 km before meeting Train Y. I don't understand is how it came out to be 15/8 . I understand that we take out speed . After that I am confused

Thanks for help

## Let's take it from 20T + (100

Let's take it from 20T + (100/3)(T) = 100 (where T = the time each train travels until they meet)

Eliminate the fraction by multiplying both sides by 3.

We get: 60T + 100T = 300

Combine: 160T = 300

Solve: T = 300/160 = 30/16 = 15/8

So, each train travels for 15/8 hours

Since train X travels at 20 km per hours, its travel distance = (speed)(time) = (20)(15/8) = 300/8 = 150/4 = 37.5 km

## Jerry and Jim run a race of

A. 8,10

B. 4,5

C. 5,9

D. 6,9

E. 7,10

## You can find my solution here

You can find my solution here: https://gmatclub.com/forum/jerry-and-jim-run-a-race-of-2000-m-first-jerr...

## Hey,

1st off, the Jerry and Jim question still gives me nightmares at night. I straight up hate that question now.

https://gmatclub.com/forum/ann-and-bea-leave-townville-at-the-same-time-and-travel-237882.html

This question however was much more to my liking.

Furthermore, out of a silly mistake I ended up finding a much easier solution.

Upon reading the question I assumed, wrongly, that the 2k distance meant 2000km. Then I assumed a value for Bee's speed, 100kmph, then naturally Anne's speed was 400kmph.

This allowed some easy arithmetic which left me with 800km as an answer; Foolishly now I checked the answer choices and found that K was in fact a variable. So I just multiplied and divided 800 by 1000. (which is 2k without the 2) replaced the numerator 1000 with K, and got 4k/5 .

Though later I realised that a much easier option would've been to see which of the answers gave me an 800 if I replaced the answer K's with 1000.

## The Jim & Jerry question

The Jim & Jerry question (here https://gmatclub.com/forum/jerry-and-jim-run-a-race-of-2000-m-first-jerr...) is a killer. Hopefully, the nightmares will subside soon :-)

As for the Ann & Bea question (here https://gmatclub.com/forum/ann-and-bea-leave-townville-at-the-same-time-...), it never dawned on me (when I created the question) that 2K might be misinterpreted as 2000, but I can totally see it now. That said, the test-makers would never assume that test-takers are aware that we can use "2K" to represent 2000

Once you realized your error, I like how you were able to use your existing calculations to determine the correct answer. Good stuff!

## My quick intuition-based

## Great logic!

Great logic!

## Add a comment