Question: Simplification with Cube Roots

Comment on Simplification with Cube Roots

Can this also be done the following way:

- Cross off one of the four 3 sq root of 6 (numerator) and the eight 3 sq root of 6 (denominator) to equal 2. Divide the 4 on the numerator by 2 on the denominator to equal E, two 3 sq root of 6

Is it safe to say:
(Cube root 6)^2/(Cube root 6) = Cube root 6
something like x^2/x = x
gmat-admin's picture

Yes, we can say that

Think of it this way:
(cube root 6)²/(cube root 6) = (cube root 6)(cube root 6)/(cube root 6)
= (cube root 6) x [(cube root 6)/(cube root 6)]
= (cube root 6) x [1]
= cube root 6

wait what, i thought (4 * 3root6)^2 is 16root6...
gmat-admin's picture

(4 x 3√6)² = (4 x 3 x √6)² = (4)² x (3)² x (√6)² = 16 x 9 x 16 = 2304

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