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## Comment on

Combining Solutions W and X## 50+0.8x = 0.4(250+x)

## Yes, that's the equation we

Yes, that's the equation we derived in the video.

## Hi Bent,

I find your approach of solving Mixture problems with diagrammatic representation very easy.Thank You.

Can you please help with the following problem:

Two alloys A and B are composed of two basic elements. The ratios of the compositions of the two basic elements in the two alloys are 5 : 3 and 1 : 2, respectively. A new alloy X is formed by mixing the two alloys A and B in the ratio 4 : 3. What is the ratio of the composition of the two basic elements in alloy X ?

(A) 1 : 1

(B) 2 : 3

(C) 5 : 2

(D) 4 : 3

(E) 7 : 9

## Tricky question!

Tricky question!

If you like the mixture technique that's shown in the video, then here's one approach:

Let's say the alloys are composed of gold and silver (in that order)

So, alloy A has a gold to silver ratio of 5 : 3

In other words, this alloy is 5/8 gold

Alloy B has a gold to silver ratio of 1 : 2

In other words, this alloy is 1/3 gold

"A new alloy X is formed by mixing the two alloys A and B in the ratio 4 : 3"

Let's combine 4 cups of alloy A with 3 cups of alloy B.

Since alloy A is 5/8 gold, then the amount of gold in 4 cups of alloy A = (5/8)(4) = 5/2 = 2.5 cups

Since alloy B is 1/3 gold, then the amount of gold in 3 cups of alloy B = (1/3)(3) = 1 cup

So, the TOTAL amount of combined gold = 2.5 + 1 = 3.5 cups.

The new mixture has a TOTAL volume of 7 cups.

If 3.5 cups is gold, then the remaining 3.5 cups must be silver.

"What is the ratio of the composition of the two basic elements in alloy X ?"

We get 3.5 : 3.5, which is the same as 1:1

Answer: A

## :D :D

I had a smile going through your explanation.

You make tricky things so easy! Thankieeee

## Brent,

Could you explain me the exercise #201 of OG17, please?

Thanks,

Pedro

## Here's my solution: https:/

Here's my solution: https://gmatclub.com/forum/a-sequence-of-numbers-a1-a2-a3-is-defined-as-...

Cheers,

Brent

## Hi Brent,

can you please solve this question, using the technique as in above video.

Jackie has two solutions that are 2 percent sulfuric acid and 12 percent sulfuric acid by volume, respectively. If these solutions are mixed in appropriate quantities to produce 60 liters of a solution that is 5 percent sulfuric acid, approximately how many liters of the 2 percent solution will be required?

Thanks

## Here's my full solution with

Here's my full solution with sketches: https://gmatclub.com/forum/jackie-has-two-solutions-that-are-2-percent-s...

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