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## Comment on

Introduction to Square Roots## Can you please help me with

Is x > y ?

(1) ✓x > y

(2) x² > y

## Tricky question! Just curious

Tricky question! Just curious, what's the source?

TARGET QUESTION: Is x > y?

STATEMENT 1: ✓x > y

There are several values x and y that satisfy statement 1. Here are two:

CASE A: x = 9 and y = 2 (notice that ✓9 = 3, and 3 is greater than 2. In this case, x > y

CASE B: x = 1/4 and y = 0.3 (notice that ✓(1/4) = 1/2, and 1/2 is greater than 0.3. In this case, x < y

Since we cannot answer the TARGET QUESTION with certainty, statement 2 is NOT sufficient.

STATEMENT 2: x² > y

There are several values x and y that satisfy statement 2. Here are two:

CASE A: x = 3 and y = 2 (notice that 3² = 9, and 9 is greater than 2. In this case, x > y

CASE B: x = 3 and y = 4 (notice that 3² = 9, and 9 is greater than 4. In this case, x < y

Since we cannot answer the TARGET QUESTION with certainty, statement 2 is NOT sufficient.

STATEMENTS 1 and 2 COMBINED

It's easy to show values of x and y that satisfy BOTH statements where x > y. For example, the following values of x and y satisfy BOTH statements:

x = 100 and y = 1

x = 16 and y = 1

x = 25 and y = -3

x = 1 and y = -30

etc

In all of the above cases, x > y

So, the correct answer MAY be C.

That said, the answer will E if there are values of x and y that satisfy BOTH statements AND where x < y

Is it possible to find such values for x and y?

No.

The tricky part is finding finding a situation where ✓x > y YET x < y

Important concept: in most cases, the square root of a number is less than the original number. For example:

✓9 < 9

✓4 < 4

✓36 < 36

The only time ✓x is GREATER THAN x is when 0 < x < 1. For example:

✓(1/4) > 1/4

✓(1/25) > 1/25

etc

So, if 0 < x < 1 then ✓x > x

The problem is that, if 0 < x < 1 then x² < x

So, any value on this range will satisfy statement 1, but will NOT satisfy statement 2.

As such, we CANNOT find values for x and y that satisfy BOTH statements such that x < y

So, it MUST be the case that, when both statements are combined, x > y

Answer: C

## Thanks Brent :)

## Hi Brent,

I couldn't find your answer to this question:

https://gmatclub.com/forum/if-x-and-y-are-positive-which-of-the-following-must-be-82080.html

Please let me know if it is already somewhere, if not, I would appreciate if you help and answer it, :

My answer is D. I and II only

There is too much debates there, it was confusing for me.

Thanks

Aladdin

## Hi Aladdin,

Hi Aladdin,

Here's my step-by-step solution: https://gmatclub.com/forum/if-x-and-y-are-positive-which-of-the-followin...

Cheers,

Brent

## Thank you so much.

## Hi Brent, could you please

If x and y are positive, which of the following must be greater than 1x+y−−−−√1x+y?

I. x+y−−−−√2x+y2

II. x√+y√2x+y2

III. x√−y√x+yx−yx+y

A. I only

B. II only

C. III only

D. I and II only

E. None

## Hi Jalaj,

Hi Jalaj,

I'd love to help you, but some of your entries are confusing and/or ambiguous.

For example, in statement I (x+y−−−−√2x+y2), is the square root over BOTH 2x and y²?

Likewise, in statement II (x√+y√2x+y2), what is inside the first square root symbol? It looks empty.

If possible, it would be great if you could find the question online and send me the link.

Alternatively, please add some brackets and spaces to prevent ambiguity.

By the way, what's the source of this question?

Cheers,

Brent

## Hi Brent, below is the source

https://gmatclub.com/forum/if-x-and-y-are-positive-which-of-the-following-must-be-82080.html

## That helps a lot.

That helps a lot.

Here's my full solution: https://gmatclub.com/forum/if-x-and-y-are-positive-which-of-the-followin...

Cheers,

Brent

## https://gmatclub.com/forum/is

sir can you please explain this?

## Here's my full solution:

Here's my full solution: https://gmatclub.com/forum/is-7x-1-2-an-integer-145680.html#p2152171

Cheers,

Brent

## Hi Brent, do you agree with

Is 7x−−√7x an integer?

(1) x7−−√x7 is an integer

(2) 28x−−−√28x is an integer

(1) Atleast 2 values of x can satisfy this condition

x=7 and x=343.

How can the answer be statement 1 is sufficient?

Similary for statement 2 x=1/28 and x=7 satisfies the condition

so if we combine 2 statements we get x=7 since x=1/28 will not satisfy statement 1!

Answer should be C right?

## I'm happy to help.

I'm happy to help.

ASIDE: In the future, please post a link to the question. I had a hard time finding the question (here it is https://gmatclub.com/forum/is-7x-1-2-an-integer-145680.html)

The correct answer is A.

Here's my full solution: https://gmatclub.com/forum/is-7x-1-2-an-integer-145680.html#p2152171

Cheers,

Brent

## I had already checked your

Its a different approach. Can you please tell me whats wrong with my approach?

For statement 1. Atleast 2 values of x can satisfy this condition

x=7 and x=343...so how is this sufficient?

## Question link: https:/

Question link: https://gmatclub.com/forum/is-7x-1-2-an-integer-145680.html

TARGET QUESTION: Is √(7x) an integer?

STATEMENT 1: √(x/7) is an integer

You're right to say that x = 7 and x = 343 both satisfy statement 1.

HOWEVER, the target question doesn't ask us to determine the value of x; the target question asks us to determine whether √(7x) is an integer.

Let's test your two results (x = 7 and x = 343)

If x = 7, then √(7x) = √(49) = 7. So, the answer to the target question is "YES, √(7x) IS an integer".

If x = 343, then √(7x) = √(2401) = 49. So, the answer to the target question is "YES, √(7x) IS an integer".

There also are other x-values that satisfy statement 1.

For example, x = 28 also works. So does x = 63

Let's test these results as well

If x = 28, then √(7x) = √(196) = 14. So, the answer to the target question is "YES, √(7x) IS an integer".

If x = 63, then √(7x) = √(441) = 21. So, the answer to the target question is "YES, √(7x) IS an integer".

Notice that, even though there are infinitely many x-values that satisfy statement 1, when we test each of these possible x-values, the answer to the target question is ALWAYS the same: "YES, √(7x) IS an integer".

In other words, it MUST be the case that √(7x) IS an integer.

Since we can answer the target question with absolute certainty, statement 1 is sufficient.

KEY TAKEAWAY: Our goal is to determine whether each statement provides enough information to answer the target question with absolute certainty.

Does that help?

Cheers,

Brent

## Thanks Brent! So the target

I think with my approach would be time consuming since I have to keep searching values of x for which it will not satisfy. There is no limit to the search. Will stick to your approach.

## That's correct. IF the target

That's correct. IF the target question asked "What is the value of x?" then statement 1 would not be sufficient.

Here are two example to highlight the key concept:

--------------------

TARGET QUESTION: If x is an integer, is x ODD?

Statement 1: x is a prime number greater than 2.

Even though there are infinitely many prime numbers greater than 2 (e.g., 3, 5, 7, 11, 13, 17, 19, 23, etc), we know that ALL prime number greater than 2 are ODD.

So, the answer to the target question is "YES, x is most definitely odd"

Statement 1 is sufficient.

--------------------

TARGET QUESTION: If x is an integer, what is the value of x?

Statement 1: x is a prime number greater than 2.

In this case, we cannot answer the target question with certainty, since x can be 3 or 5 or 7 or 11 or 13 or . . .

Statement 1 is not sufficient.

Cheers,

Brent

## Thanks Brent

Sorry, one final time going back to the original question from GMAT club, this time for statement 2. the approach used is testing some values of x. But can we not use the same approach as we did for statement 1 which is solving the equation?

So it will go as:

let integer be p

so √(28x)=p

square both sides

28x=p²

7.4x=p²

7x=(p²)/4

take square root both sides

√(7x)=p/2=0.5p...not an integer

Not sufficient?

## Question link: https:/

Question link: https://gmatclub.com/forum/is-7x-1-2-an-integer-145680.html

Great idea!

I'd make just one small change to your approach:

At the end, once we know that √(7x) = p/2, we can't conclude that p/2 is NOT an integer.

For example, if p = 14, then p/2 IS an integer.

Conversely, if p = 3, then p/2 is NOT an integer.

Now that we have two contradictory answers to the target question, we can be certain that statement 2 is not sufficient.

Cheers,

Brent

## Oh yes, thanks for the heads

Not sufficient implies not getting a unique solution! we need atleast one "not" and atleast one "is" an integer

## Exactly!

Exactly!

## Hi Brent,

say we have

1/x= 1/(x+15)+ 1/(x-4)

The on solving this we get

x^2= -60

Does this mean there is no solution for x

## That's correct; the equation

That's correct; the equation x² = -60 has no real solutions.

Cheers,

Brent

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