Lesson: Finding the Average Speed

Comment on Finding the Average Speed

Hi, I solved the Yoshi avg speed in another almost similar way: as the question says, the speed Yoshi traveled from Twnsville to Villageton was 20mile/hour

This means the distance between the two cities is 20 mile. as though, the total distance is 20*2=40. for total time I just added 1 hour plus 1/4 of the hour on the way back as he was 4 times faster.

Then using the formula avg speed=total dist/total time

=40/(5/4)= 160/5= 32

What do you think?
gmat-admin's picture

Great approach, Zoser.

Since we aren't told the distance between Townville and Villageton, you assigned an arbitrary value of 20 miles to the distance and performed the necessary calculations.

Another useful value you could have assigned to the distance between Townville and Villageton is 80 miles.

In this case, the time TO Villageton = 80/20 = 4 hours, and the time back TO Townville = 80/80 = 1 hour.

So average speed = (total distance)/(total time)
= (80 + 80)/(4 +1)
= 160/5
= 32 miles per hour

Thanks a lot.

I dont understand why the d`s cancel out. could you please help?
gmat-admin's picture

I believe you're referring to the expression 2d x 80/5d

NOTE: This is equivalent to 2d/1 x 80/5d

There are a couple of ways to deal with this.

APPROACH #1: Multiply the fractions.
We get: 2d/1 x 80/5d = 160d/5d
Divide to and bottom by d to get: 160/5
Divide to and bottom by 5 to get: 32/1 (which is equal to 32)

APPROACH #2: Simplify the fractions BEFORE multiplying (see 4:35 of https://www.gmatprepnow.com/module/gmat-arithmetic/video/1068)
Start with 2d/1 x 80/5d

Take 2d and 5d and divide both by d to get 2 and 5

So, we have: 2d/1 x 80/5d = 2/1 x 80/5
= 160/5
= 32

For more information on working with fractions, see https://www.gmatprepnow.com/module/gmat-arithmetic/video/1065 and https://www.gmatprepnow.com/module/gmat-arithmetic/video/1068

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