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## Comment on

Exponent Laws - Part I## The value of 12! is closest

A. (10^6)

B. 3(10^7)

C. 5(10^8)

D. 7(10^9)

E. 9(10^11)

Hi Brent,

I did not understand your approach to solve this question. What is 12!

Grateful for your help on this

Fatima-Zahra

## Question link: https:/

Question link: https://gmatclub.com/forum/the-value-of-12-is-closest-to-233527.html

Good question, Fatima-Zahra.

In general, n! (read as "n factorial") is the product of all of the positive integers from 1 to n.

So, for example, 4! = 4 x 3 x 2 x 1

7! = 7 x 6 x 5 x 4 x 3 x 2 x 1

and 12! = 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

More on factorial notation: https://www.gmatprepnow.com/module/gmat-counting/video/780

Cheers,

Brent

## Hi Brent, could you explain

## Sorry Jalal, but I'm not sure

Sorry Jalal, but I'm not sure what you mean by "solve a factorial number."

If you mean how to evaluate (e.g., 3! = 6), then I cover that in my post here: https://gmatclub.com/forum/the-value-of-12-is-closest-to-233527.html#p18...

Cheers,

Brent

## Hi Brent,

In the below DS question I know the answer is B but I failing to get a definite answer out of B. Need your help.

https://gmatclub.com/forum/is-5-k-less-than-144719.html

## Here's my full solution:

Here's my full solution: https://gmatclub.com/forum/is-5-k-less-than-144719.html#p1996771

Cheers,

Brent

## For (12^8)/(2^3)

can you do this?

(6^8)(2^8)/(2^3)= (6^8)(2^5)= 53,747,712?

## You bet!

You bet!

Rewriting 12^8 as (6^8)(2^8) is an application of the Combining Bases law (more here: https://www.gmatprepnow.com/module/gmat-powers-and-roots/video/1029)

And simplifying (2^8)/(2^3)to get 2^5 is an application of the Quotient law.

Cheers,

Brent

## HI Brent can u solve this

2^(4−1)^2 /2^(3−2)=

A. 2^8

B. 2^7

C. 2^6

D. 2^5

E. 2^4

## Question link: https:/

Question link: https://gmatclub.com/forum/2-104427.html

IMPORTANT: I'm adding some square brackets to show that we are squaring the value of (4-1)

We have: 2^[(4−1)^2]/2^(3−2)

Evaluate parts in bracket: 2^[(3)^2]/2^(1)

Evaluate again: (2^9)/(2^1)

Apply Quotient Law: 2^8

Answer: A

Cheers,

Brent

## Hi Brent, will practicing

If I start practicing all the problems given in the link, it will take a lot of time to complete one single topic

## For the most part, I believe

For the most part, I believe there are enough practice questions in the Reinforcement Activities boxes beneath most video lessons.

Even if you were to answer only half of thos 420e linked practice questions, I believe that would be sufficient.

That said, GMAT Club is an excellent resource for extra questions.

If you find that this strategy will take too long, another approach is to keep answering practice questions within your target score range until you correctly answer 3 questions in a row. Doing so should demonstrate a reasonable mastery of that concept.

## Hi Brent,

https://gmatclub.com/forum/if-x-p-and-q-are-positive-integers-then-226869.html

If x , p and q are positive integers , then x^p/x^q = ?

1. p = q + 5

2. x^q = 32

Could you please tell where I am making a mistake?

The question is x^(p-q) = ?

Statement 1: p = q + 5

p - q = 5

x^(p-q) = x^5, we don't know anything about x -> Insufficient

Statement 2: x^q = 32

x^q = 2^5

No info about q -> Insufficient

Both statement:

x^q = 2^5

x^(p-q) = x^5, no info to answer the question

OR

x^p/x^q = x^p/32= x^p/2^5, still no info about ^p.

Answer is E.

Brent I have a separate question if we have x^p = 2^5 can we assume that base x is also 2?

## Question link: https:/

Question link: https://gmatclub.com/forum/if-x-p-and-q-are-positive-integers-then-22686...

Your reasoning/solution is perfectly valid.

Q: If we have x^p = 2^5 can we assume that base x is also 2?

No, If x^p = 2^5, it COULD be the case that x = 2 and p = 5, but it COULD also be the case that x = 32 and p = 1 (since 32^1 = 2^5 = 32)

## Hey Brent,

I may have missed something, but do you reference the rules when raised to a negative exponent?

This is in reference to one of the reinforcement activities : 8^a*(1/4)^b = ?

I now understand the approach but want to familiarize myself with the theory. Thank you in advance!

## Good catch! I shouldn't have

Good catch! I shouldn't have that question here, since it requires knowledge of negative exponents (which happens to be the next video lesson after this one).

I've moved the question so that it's under the Negative Exponents lesson.

Thanks for the heads up.

## https://gmatclub.com/forum/r

Had to say that I got real panic when I saw this, and don't know what to do. my brain is like totally blank.

Even if I knew 81 is 3^4, I'm not sure what rule I can have, it seems like it's product law, but that's like completely new form to think about it...

## Question link: https:/

Question link: https://gmatclub.com/forum/r-3-81-r-r-3-s-s-92651.html

It's a difficult question.

The more questions you see of this nature, the more accustomed you will be to finding the solution.

## OK so for this question https

I didn't modify anything (but it could be my own risks)

so the target question asks if x>3.

first one calculate if x = 2 or less then it CANNOT be greater than 9800 because I calculated it.

if the first one is correct, then second one makes sense because if x is 2 or less then it CANNOT be greater than 10000

## Question link: https:/

Question link: https://gmatclub.com/forum/is-7-x-100-1-7-x-2-9-800-2-7-2x-309930.html

The original target question is "Is 7^x > 100?"

Rephrasing the target question to get "Is x > 3?" isn't quite right.

If x = 3, then 7^3 > 100, so, x = 3 is also allowed.

I'm not sure if I follow the rest of your solution.

## OK, just went through your

## https://gmatclub.com/forum

I understand your solution***

Well, but I don't think I can perform it on the test day, i'm not that flexible and if I try to modify it then it can be the case that none of my modified version accordance with answer choices.

## Question link: https:/

Question link: https://gmatclub.com/forum/the-value-of-12-is-closest-to-233527.html

If you're truly saying "I'm incapable of learning this new technique," then you might want to stick with performing all of the lengthy calculations.

## no obviously I'm not..., I do

## OK so my one is not exactly

SO, 11*9 = 100, 12*8 =100, 7*5*3 = 100, 4*6*2*10 = 480

total = 480000000 = 5 * 10^8

## Yes, there are several

Yes, there are several different ways we can approach this question.

Your approach is perfect. Great job!