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## Comment on

Exponent Laws - Part II## I love the fact that you have

## Thanks! We're adding

Thanks! I'm adding questions every day.

## Hi Brent.

I am confused on your answer to this question

https://gmatclub.com/forum/if-5-13-9-7-3-15-x-what-is-the-value-of-x-219722.html

We can answer this question by keeping track of the 5's only.

Given: (5^13)(9^7)=3(15^x)

Rewrite as: (5^13)(9^7)=3(5^x)(3^x)

So, it must be true that (5^13) = (5^x)

So, x = 13

## Question link: https:/

Question link: https://gmatclub.com/forum/if-5-13-9-7-3-15-x-what-is-the-value-of-x-219...

Good question.

When I get to (5^13)(9^7)=3(5^x)(3^x), I can see that, if I were to write the LEFT side of this equation as the product of 5's and 9's, I'd have THIRTEEN 5's and SEVEN 9's.

Likewise, I were to write the RIGHT side as the product of 5's and 3's, I'd have x 5's and (x+1) 3's.

Since the left side EQUALS the right sides, it must be the case that we have the same number of 5's on each side.

In other words, it must be true that x = 13

Does that help?

Cheers,

Brent

## Hey Brent,

I am trying to solve the following question:

If (1/5)^m * (1/4)^18 = 1/(2(10))^35 , then m =

17

18

34

35

36.

I have simplified the right side to 1/2 * 10^(-35) but I cannot figure out how to proceed. I've looked through the videos but can't finde a suitable one. Any solutions and video recommendations on this topic are greatly appreciated.

Cheers,

Kevin

## Here's my full solution:

Here's my full solution: https://gmatclub.com/forum/if-1-5-m-1-4-18-1-2-10-35-then-m-127321-20.ht...

Cheers,

Brent

## Thank you Brent, as always

## Hello Brent,

If d=1/(2^3*5^7) is expressed as a terminating decimal, how many nonzero digits will d have?

Given d= 1/(2^3*5^7) i

Multiply by 2^4/ 2^4

d=2^4/(2^3∗5^7)∗2^4=

2^4/ 2^7 ∗ 5^7 =

2^4/ 10^7 = 16 / 10^7 = 0.0000016

Hence D will have two non-zero digits, 16, when expressed as a decimal.

I have a question concerning the solution, why do we ignore the multiplication of 2^4 x 5^7 ?

Thank you

## Here's my full solution:

Here's my full solution: https://gmatclub.com/forum/if-d-1-2-3-5-7-is-expressed-as-a-terminating-...

Please let me know if you have any questions about it.

Cheers,

Brent

## Hi Brent,

Could you please help me with this question?

https://gmatclub.com/forum/if-y-k-y-5k-m-what-is-k-248526.html

If y^k/y^5k = y^m, what is k?

(1) m = 4

(2) y = 4

Of course I applied the exponent law. In your solution you said "we must be certain that the base does not equal 0, 1 or -1, in which case the exponent laws fly out the window."

Do I always keep it in mind when in the question variables are presented as a base? When the base is zero then the result would be equal to zero despite the exponent?

## Question link: https:/

Question link: https://gmatclub.com/forum/if-y-k-y-5k-m-what-is-k-248526.html

Q: Do I always keep it in mind when in the question variables are presented as a base? When the base is zero then the result would be equal to zero despite the exponent?

Yes, that's correct.

For example, if we know that 1^x = 1^y, we can't make any conclusions about whether x = y (since 1^x and 1^y evaluate to be 1 for ALL values of x and y.

Likewise, if we're given the equation w^x = w^y, we can't make any conclusions about whether x = y, since we don't know anything about the value of w.

Cheers,

Brent

## Hi Brent,

I have a query with the below question:

Is y^x > x^y?

(1) y > x

(2) x is a positive number

Initially, while I was working this out, I thought the answer would be C - but then realized that I didn't consider a case where x=2 & y=4 which would result in y^x < x^y.

My question is that how can we identify what will be the right set of values to put in place of x and y to explore the different answers we may get for the x^y & y^x?

Since there could be so many different combinations of X & Y, how can we figure out the possibly good numbers to choose given that we have to finish this question in about 2 mins?

## Question link: https:/

Question link: https://gmatclub.com/forum/is-y-x-x-y-249057.html

Good question. Testing values can definitely take a while, but there are a few guidelines to consider that may help speed up the process (these are covered in the following video on "good" numbers: https://www.gmatprepnow.com/module/gmat-data-sufficiency/video/1102)

Let's start with two small numbers that are close together.

If x = 1 and y = 2, then x^y = 1^2 = 1, and y^x = 2^1 = 2

So, the answer to the target question is, "YES, y^x > x^y"

From here, let's test one small number and one large number.

If x = 2 and y = 10, then x^y = 2^10 = some huge number, and y^x = 10^2 = 100

So, the answer to the target question is, "NO, it is not the case that y^x > x^y"

Answer: E

The main idea here, is to test different pairs of numbers.

Some examples include:

- Two positive values

- Two negative values

- One small positive value and one large positive value

- One positive fractional value and one large positive value

- One negative value and one positive value

etc.

## Alright got it, I guess a lot

## Hi Brent,

Could you help me with this question?

If 5^11 × 4^5 = 5 × 10^k, what is the value of k?

I started doing the following:

5^11 x (2^2)^5 = 5 × 10^k

5^11 x 2^10 = 5 x 10^k

And then got stuck! Thanks.

## What's the source of this

I'm happy to help.

Given: 5^11 × 4^5 = 5 × 10^k

Divide both sides by 5 to get: 5^10 × 4^5 = 10^k

Rewrite 4 as 2^2 to get: 5^10 × (2^2)^5 = 10^k

Simplify to get: 5^10 × 2^10 = 10^k

Since both terms on the left side have the same exponent we can rewrite as: (5 x 2)^10 = 10^k

Simplify: 10^10 = 10^k

This means k = 10

Cheers,

Brent

## Brent,

My mistake, I typed it in a very confusing format! It is indeed a PS question. The 1 & 2 were just showcasing my attempted steps.

I understand the solution now, thank you for your help!!

## Ahhh, that makes sense :-)

Ahhh, that makes sense :-)

I've edited your original post as well as my reply. (I'll delete these last two comments so as not confuse anyone :-)

Cheers,

Brent